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The phase difference between two waves, represented by [2004]
y1 = 10–6 sin{100 t + (x/50) + 0.5} m
y2 = 10–6 cos{100 t + (x/50)} m
where x is expressed in metres and t is expressed in seconds, is approximately [2004]
  • a)
    1.5 radians
  • b)
    1.07 radians
  • c)
    2.07 radians
  • d)
    0.5 radians
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The phase difference between two waves, represented by [2004]y1 = 10&n...
y1 = 10–6 sin (100t + x/50 + 0.5)m
= 10–6 cos (100t + x/50 – π/2 + 0.5)m
y2  = 10–6 cos (100t + x/50)m
∴ φ = π/2 – 0.5 = 1.07 rad
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The phase difference between two waves, represented by [2004]y1 = 10–6 sin{100 t + (x/50) + 0.5} my2 = 10–6 cos{100 t + (x/50)} mwhere x is expressed in metres and t is expressed in seconds, is approximately [2004]a)1.5 radiansb)1.07 radiansc)2.07 radiansd)0.5 radiansCorrect answer is option 'B'. Can you explain this answer?
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